Two children on racing bikes start from the same refrence point. child A travels 5.0 meters per second right and child B travels 4.5 meters per second right.
howmuch farther from the oint of origin is child a than child b after 5 seconds
Technically, you cannot tell. You have to add the assumption that they both also started at the same time in order to get an answer.
First, use the equation d = r * t for both to determine the distance each traveled.
Child a: d = r * t = 5.0 meters per second * 5 seconds = 25 meters
Child b: d = r * t = 4.5 meters per second * 5 seconds = 22.5 meters
2) Now just figure out how much farther the first child went than the second child
To find out how much farther Child A is from the point of origin compared to Child B after 5 seconds, we first need to calculate the total distance traveled by each child.
Child A has a velocity of 5.0 meters per second and travels for 5 seconds, so the distance traveled by Child A is given by:
Distance_A = Velocity_A × Time = 5.0 m/s × 5 s = 25 meters.
Similarly, Child B has a velocity of 4.5 meters per second and travels for 5 seconds, so the distance traveled by Child B is given by:
Distance_B = Velocity_B × Time = 4.5 m/s × 5 s = 22.5 meters.
Now we can determine how much farther Child A is from the point of origin compared to Child B by subtracting the distance traveled by Child B from the distance traveled by Child A:
Difference = Distance_A - Distance_B = 25 meters - 22.5 meters = 2.5 meters.
Therefore, Child A is 2.5 meters farther from the point of origin than Child B after 5 seconds.