what is the total numbers of liters of N0(g)produced when 2.0 liters of N2 reacts completely with oxygen?
N2(g)+O2-2NO(g)
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When all of the reagents are gases, you may use liters as you would moles; therefore, 2 liters N2 will produce 4 liters of NO.
To find the total number of liters of N0(g) produced when 2.0 liters of N2 reacts completely with oxygen, we need to use the stoichiometry and balanced equation of the reaction.
In the balanced equation:
N2(g) + O2(g) -> 2NO(g)
The coefficient of N2 is 1, which means that 1 mole of N2 reacts to produce 2 moles of NO.
We can use the concept of molar volume to convert between moles and liters. At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.
To find the answer, we follow these steps:
1. Convert 2.0 liters of N2 to moles using the molar volume at STP.
2.0 liters of N2 x (1 mole N2 / 22.4 liters N2) = 0.089 moles of N2
2. Use the stoichiometry of the balanced equation to determine the number of moles of NO produced. Since the ratio of N2 to NO is 1:2, the number of moles of NO will also be twice the number of moles of N2.
Moles of NO = 0.089 moles of N2 x 2 = 0.178 moles of NO
3. Convert moles of NO back to liters using the molar volume at STP.
0.178 moles of NO x (22.4 liters NO / 1 mole NO) = 3.99 liters of NO
Therefore, when 2.0 liters of N2 reacts completely with oxygen, approximately 3.99 liters of NO gas will be produced.