An electrostastic force of 20.0 newtons is exerted on a charge of 8.00 x 10^/2 C at point P in an electric field. The magnitude of the electric field strength at P is
Given:
Fe = 20 B
q = 8.00 x 10^/2 C
Use F = Q * E
Solve for E, in Newtons per Coulomb
Fe = 50 N(ewtons), NOT 50 B
I think you made a typing error
I do not understand why you put an / in front of the exponent, 2, of the charge (Q)
Oh im really sorry, its 8.00 x 10^-2
To find the magnitude of the electric field strength at point P, we can use the equation:
E = Fe / q
where E is the electric field strength, Fe is the electrostatic force, and q is the charge.
In this case, we are given Fe = 20 N and q = 8.00 x 10^/2 C.
Substituting these values into the equation, we have:
E = 20 N / (8.00 x 10^/2 C)
Now, let's simplify the expression:
E = 20 N / (0.08 C)
Dividing 20 N by 0.08 C gives us:
E = 250 N/C
Therefore, the magnitude of the electric field strength at point P is 250 N/C.