I am given the following:
0.20 M BaCl2
0.60 M H2SO4
1 M of HCl
Assuming that you are working with 1 mL of barium chloride, calculate the theoretical number of grams of barium sulfate that should be produced. what is the limiting reactant?
so far i have BaCl2 (aq) + H2SO4 --> BaSO4 + 2HCl
then i calculated
0.20 = x/.001L
so the # of mols is .0002
am i doing this correctly? what do i need to do next? thanks!
So far so good.
Next convert 0.0002 mols BaCl2 to moles BaSO4 using the coefficients in the balanced equation. The reactin is 1:1; therefore, you will have 0.0002 moles BaSO4 produced. Then convert that to grams by g = moles x molar mass. The limiting reagent must be BaCl2 since that is the only reactant listed. Perhaps you omitted the amount of H2SO4 from the problem.
Yes, you are on the right track! You correctly calculated the number of moles of BaCl2. Now, to determine the theoretical number of grams of barium sulfate produced, we need to use the stoichiometry of the balanced equation.
The balanced equation is:
BaCl2 + H2SO4 -> BaSO4 + 2HCl
From the balanced equation, we can see that the mole ratio between BaCl2 and BaSO4 is 1:1. Since you have calculated the number of moles of BaCl2, which is 0.0002 moles, you can conclude that you would produce 0.0002 moles of BaSO4.
To convert moles of BaSO4 to grams, you need to use the molar mass of BaSO4, which is 233.39 g/mol.
Grams of BaSO4 = moles of BaSO4 × molar mass of BaSO4
= 0.0002 moles × 233.39 g/mol
= 0.04668 g (rounded to four decimal places)
So, theoretically, you would produce approximately 0.0467 grams of BaSO4.
To determine the limiting reactant, you need to compare the number of moles of each reactant with their respective stoichiometric coefficients. In this case, you already have the moles of BaCl2 (0.0002 moles), but you also need to calculate the moles of H2SO4 and HCl.
For H2SO4:
0.60 M H2SO4 = 0.60 moles/L
0.60 moles/L × 0.001 L = 0.0006 moles
For HCl:
1 M HCl = 1 mole/L
1 mole/L × 0.001 L = 0.001 moles
Now, compare the moles of each reactant with their stoichiometric coefficients in the balanced equation to find the limiting reactant. The stoichiometric coefficient of BaCl2 is 1, so it will be the limiting reactant if it has the lowest number of moles.
Given:
Moles of BaCl2: 0.0002
Moles of H2SO4: 0.0006
Moles of HCl: 0.001
Since the moles of BaCl2 are the lowest, BaCl2 is the limiting reactant.
Remember, this calculation assumes ideal conditions and that all reactions proceed to completion.