Two small planes start from the same point and fly in the same direction. The first plane is flying 35 mph slower than the second plane. In 2 hrs, the planes are 530 mi apart. Find the rate of the slow plane.
v*2 + (v+35)2=530miles
To solve this problem, we can use the formula for calculating relative speed:
Relative Speed = Distance / Time
Let's assume the speed of the second plane is x mph. Since the first plane is flying 35 mph slower, the speed of the first plane would be (x - 35) mph.
Using the formula above, we can calculate the distance each plane has traveled:
Distance of the first plane = Speed of the first plane x Time = (x - 35) mph x 2 hours = 2x - 70 miles
Distance of the second plane = Speed of the second plane x Time = x mph x 2 hours = 2x miles
The total distance traveled by both planes is given as 530 miles. So, we can write the equation:
Distance of the first plane + Distance of the second plane = Total distance
(2x - 70) miles + 2x miles = 530 miles
Combine like terms and solve for x:
4x - 70 = 530
4x = 600
x = 150
So, the speed of the second plane is 150 mph.
To find the speed of the first plane, which is 35 mph slower, we subtract 35 from the speed of the second plane:
Speed of the slow plane = Speed of the second plane - 35 = 150 mph - 35 mph = 115 mph
Therefore, the rate of the slow plane is 115 mph.