Calculate the Magnitude of the resultant of a pair of 100-km/h velocity vectors that are at right angles to each other.
Use Pyth theorm.
Calculate the magnitude of the resultant of a pair of 100-km/h velocity vectors that are at right angles to each other.
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To calculate the magnitude of the resultant of two velocity vectors at right angles to each other, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the two velocity vectors are at right angles to each other, so we have a right triangle. Let's call the magnitude of the first velocity vector V1 and the magnitude of the second velocity vector V2. We want to find the magnitude of the resultant, which we'll call VR.
According to the Pythagorean theorem, VR^2 = V1^2 + V2^2
In our case, both V1 and V2 are given as 100 km/h.
VR^2 = (100 km/h)^2 + (100 km/h)^2
VR^2 = 10000 km^2/h^2 + 10000 km^2/h^2
VR^2 = 20000 km^2/h^2
To find VR, we can take the square root of both sides of the equation:
VR = √(20000 km^2/h^2)
VR ≈ 141.42 km/h
Therefore, the magnitude of the resultant of the pair of 100-km/h velocity vectors that are at right angles to each other is approximately 141.42 km/h.