i need help sovling for these variables(i know that i am supposed to solve usign opposite operartion but i keep getign most of them wrong.
A= 1/2 (a+b)h find a
A= 1/2 (a+b)h find h
T= squareroot I find I
V= 4/3pier^2 find r
This is Physics?
I can't help you unless I know what is wrong. Do one, show your work.
for A= 1/2 (a+b)h find h
is this right h= A/(1/20(a+b)
No. multipy both sides by 2, divide both sides by (a+b)
h= 2A/(a+b)
I recommend you get a math tutor immediatiely, this is stock algebra I. You will have great difficulty in physics with your level of math skills.
To solve for the variables in the given equations, you can follow these steps:
1. A = (1/2)(a + b)h - Find a:
To isolate the variable 'a', you can follow the steps below:
a. Multiply both sides of the equation by 2 to get rid of the fraction: 2A = (a + b)h.
b. Distribute 'h' to both 'a' and 'b': 2A = ah + bh.
c. Subtract 'bh' from both sides of the equation: 2A - bh = ah.
d. Finally, divide both sides of the equation by 'h' to solve for 'a': a = (2A - bh) / h.
2. A = (1/2)(a + b)h - Find h:
To isolate the variable 'h', you can follow the steps below:
a. Multiply both sides of the equation by 2 to get rid of the fraction: 2A = (a + b)h.
b. Divide both sides of the equation by (a + b) to solve for 'h': h = 2A / (a + b).
3. T = √I - Find I:
To solve for 'I' in the equation T = √I, you need to eliminate the square root. Here are the steps:
a. Square both sides of the equation to remove the square root: T^2 = I.
b. Therefore, I = T^2.
4. V = (4/3)πr^2 - Find 'r':
To solve for 'r' in the equation V = (4/3)πr^2, you need to isolate the variable 'r'. Follow these steps:
a. Divide both sides of the equation by (4/3)π to eliminate it: V / (4/3)π = r^2.
b. Take the square root of both sides of the equation to solve for 'r': √(V / (4/3)π) = r.
Remember to double-check your calculations to avoid errors, and if you encounter complex equations or expressions, use a calculator for accuracy.