calculate the change in thermal energy of the water in a pound with a mass of 1000kg and a specific heat of 4184 j(kg)if the water cools by 1c
heat=mass*specific heat*changeinTemp
To calculate the change in thermal energy of the water, you can use the equation:
Q = m * c * ΔT
Where:
Q is the change in thermal energy (in joules)
m is the mass of the water (in kilograms)
c is the specific heat capacity of water (in J/(kg°C))
ΔT is the change in temperature (in °C)
Given:
m = 1000 kg
c = 4184 J/(kg°C)
ΔT = -1 °C (since the water cools by 1 °C, there is a negative change)
Now, substitute the given values into the equation:
Q = 1000 kg * 4184 J/(kg°C) * (-1 °C)
Calculate the result:
Q = -4,184,000 J
Therefore, the change in thermal energy of the water is -4,184,000 joules.
To calculate the change in thermal energy of the water, you can use the formula:
ΔQ = mcΔT
Where:
ΔQ is the change in thermal energy,
m is the mass of the water in kilograms,
c is the specific heat capacity of water (which is 4184 J/(kg·°C)), and
ΔT is the change in temperature in degrees Celsius.
Given the information:
m = 1000 kg
c = 4184 J/(kg·°C)
ΔT = -1°C (since the water is cooling, the change in temperature is negative)
Plugging in these values into the formula, we have:
ΔQ = (1000 kg) × (4184 J/(kg·°C)) × (-1°C)
Calculating it, we find:
ΔQ = -4,184,000 J
Therefore, the change in thermal energy of the water is -4,184,000 Joules. The negative sign indicates that the water is losing thermal energy as it cools.