solve for x

8x-(2x-1)=3x-10

To solve for x in the equation 8x - (2x - 1) = 3x - 10, you can follow these steps:

Step 1: Distribute the negative sign to the terms inside the parentheses:

8x - 2x + 1 = 3x - 10

Simplifying, we get:

6x + 1 = 3x - 10

Step 2: Move the variable terms to one side and the constant terms to the other side of the equation. To do this, subtract 3x from both sides:

6x - 3x + 1 = 3x - 3x - 10

Simplifying, we get:

3x + 1 = -10

Step 3: Move the constant term to the other side of the equation by subtracting 1 from both sides:

3x + 1 - 1 = -10 - 1

Simplifying, we get:

3x = -11

Step 4: Solve for x by dividing both sides of the equation by 3:

3x/3 = -11/3

Simplifying, we get:

x = -11/3

Therefore, the solution for x is x = -11/3.

I will be happy to critique your work.

I am somewhat bothered by your subject: precal. This question is standard stock for Algebra I.