Please help me, help my son:
a(a-c)=23, solve for the value of c
Thanks
Since 23 is a prime number it can only have two factors: 23 and 1. Therefore, A must equal 23 and C must equal 22.
a(a-c)=23
a-c=23/a
c=a-23/a
Ik this is 13 yrs old and your son did this problem before I was born (im 12) but the answer is 23/a
To solve for the value of c in the equation a(a-c) = 23, we can use the following steps:
Step 1: Distribute the value of a to remove the parentheses.
a * a - a * c = 23
Step 2: Simplify the equation.
a^2 - ac = 23
Step 3: Move all terms to one side of the equation to set it equal to zero.
a^2 - ac - 23 = 0
Step 4: This equation is a quadratic equation in terms of c. To solve it, we can use the quadratic formula:
c = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, the values are:
a = 1
b = -a = -1
c = -23
Substitute these values into the quadratic formula.
c = (-(-1) ± √((-1)^2 - 4(1)(-23))) / (2*1)
Simplify the equation:
c = (1 ± √(1 + 92)) / 2
Further simplification:
c = (1 ± √93) / 2
Therefore, the solution for the value of c is given by:
c = (1 + √93) / 2 or c = (1 - √93) / 2