I have tried to solve this problem, but I keep getting it wrong. Please advise on this question.My answer will be listed under the problem.
An ore contains 2.79 g of silver per ton of ore. What is the concentration of silver in ppm?
My Answer: 0014164.8
I don't like to use ppm BUT 1 ppm = 1 part per 1,000,000 parts and it's easier to just say 1 gram per 1,000,000 grams. So 2.79 g Ag in 2,000 g ore is the same as 1395 g Ag in 1,000,000 g ore. Just set up a proportion like this
(2.79 g Ag/2,000 ore) = (x g Ag/1,000,000 g ore) and solve for x.
To find the concentration of silver in parts per million (ppm), you can use the following formula:
Concentration (ppm) = (Mass of Silver / Mass of Ore) x 1,000,000
Given that the ore contains 2.79 g of silver per ton of ore, we can proceed with the calculations:
1. First, convert the mass of silver from grams to milligrams, as ppm is usually expressed in milligrams per kilogram:
Mass of Silver = 2.79 g × 1000 mg/g = 2790 mg
2. Next, convert the mass of the ore from tons to kilograms, as ppm is usually expressed in milligrams per kilogram:
Mass of Ore = 1 ton × 1000 kg/ton = 1000 kg
3. Now, substitute the values into the formula:
Concentration (ppm) = (2790 mg / 1000 kg) x 1,000,000 = 2790 ppm
Therefore, the correct concentration of silver in the ore is 2790 ppm. Your answer of 0014164.8 is incorrect.