Add: b^−3 ca^−1 −xc^−2
how would i do this ?
Let me make sure I have the question right. We have
b^(−3) ca(^−1) −xc^(−2 )=?
You might also write this as
(1/b^3) c(1/a) − x(1/c)=
c/(a*b^3) - x/c=?
If this is correct, then find a common denominator and do the subtraction. If I got the question wrong then repost it.
hhh
To add the given expression b^(-3)ca^(-1) - xc^(-2), you need to follow these steps:
1. Simplify the exponents:
- The negative exponent b^(-3) can be rewritten as 1/b^3.
- The negative exponent a^(-1) can be rewritten as 1/a.
- The negative exponent c^(-2) can be rewritten as 1/c^2.
2. Rewrite the expression using the simplified exponents:
1/b^3 * ca * 1/a - x * 1/c^2
3. Multiply the terms together:
(ca/b^3a) - (x/c^2)
4. Combine like terms if possible:
ca/b^3a - x/c^2
5. To simplify this further, find a common denominator by multiplying the denominators:
(ca * c^2)/(b^3a * c^2) - (x * b^3a)/(c^2 * b^3a)
6. Simplify the expression by multiplying out the numerators and denominators:
(c^3a)/(b^3ac^2) - (x * b^3a)/(c^2 * b^3a)
7. Combine like terms:
(c^3a)/(b^3ac^2) - (xb^3a)/(c^2b^3a)
8. Simplify further if possible, by canceling out common factors:
c/b^3c^2 - x/c^2
9. Simplify the expression by performing the specified operations:
(c - x)/(b^3c^2)
So, the simplified expression is (c - x)/(b^3c^2).