Math

The average of a set of five different positive integers is 360. The two smallest integers in the set are 99 and 102. What is the largest possible integer in this set?

asked by Mark
  1. 360*5-sum2= sumlastthree
    1800-201=
    1599 = sumlast three
    But all have to be greater than 102
    so let the first two be 102, 103, lowest that they can be.
    1599-102-103= last digit.

    so figure the last digit.

    posted by bobpursley

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