Math

The average of a set of five different positive integers is 360. The two smallest integers in the set are 99 and 102. What is the largest possible integer in this set?

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asked by Mark
  1. 360*5-sum2= sumlastthree
    1800-201=
    1599 = sumlast three
    But all have to be greater than 102
    so let the first two be 102, 103, lowest that they can be.
    1599-102-103= last digit.

    so figure the last digit.

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    posted by bobpursley

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