# physics

A proton is released at the origin in a constant electric field of 850 N/C acting in the positive x-direction. Find the change in the electric potential energy associated with the proton after it travels to x = 2.5 m.

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1. The electric potential decreases by an amount q E * (2.5 m)

q is the electron charge with a plus sign (for the proton charge), in Coulombs. E is the electric field strength, in N/C.

The Potential Energy decreases because the field does work on the proton when moving in the +x axis direction

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posted by drwls
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posted by er

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