If the density of mercury is 13.6 g/ml, what is the mass of 3.0 liters of mercury in:

Grams?
Pounds?

13.6g/ml * 1000ml/l * 3l

There are 453.6 g in a pound.

?g Hg x (1 lb/453.6 g) = xx lb Hg.

the density of platinum is 23.4 g /cm3

To find the mass of 3.0 liters of mercury, we can use the formula:

Mass = Density x Volume

First, let's calculate the mass in grams:

1. Convert liters to milliliters:
Since 1 liter is equal to 1000 milliliters, we can calculate:
3.0 liters x 1000 ml/liter = 3000 ml

2. Multiply the density by the volume:
Mass = 13.6 g/ml x 3000 ml = 40800 grams

Therefore, the mass of 3.0 liters of mercury is 40800 grams.

Now, let's calculate the mass in pounds:

1. Convert grams to pounds:
Since 1 pound is equal to 453.592 grams, we can calculate:
40800 grams / 453.592 grams/pound = 90 pounds (rounded to two decimal places)

Therefore, the mass of 3.0 liters of mercury is approximately 90 pounds.