Two helicopters leave Springfield, IL at the same time. One travles north at 27 miles per hour and the other travels west at 120 miles per hour. How far apart are they after 3 hrs?
(Hint: Use d=rt to find the distance traveled by each helicopter.)
I know that d=27*3, d=81 and
d=120*3= 360
these are the choices
f. 374 miles
g. 366 miles
h. 369 miles
j. 379 miles
you have a right-angled triangle
Use Pythagoras to find the hypotenuse
To find the distance between the two helicopters after 3 hours, we need to use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, the distances traveled by the helicopters form the legs of a right triangle. The helicopter traveling north has traveled 81 miles (27 miles per hour * 3 hours), and the helicopter traveling west has traveled 360 miles (120 miles per hour * 3 hours). We need to find the distance between them, which is the hypotenuse.
Using the Pythagorean theorem equation, we can calculate the length of the hypotenuse:
distance^2 = (81 miles)^2 + (360 miles)^2
distance^2 = 6561 miles^2 + 129600 miles^2
(distance^2 = 136161 miles^2)
Taking the square root of both sides to solve for the distance:
distance = √(136161 miles^2)
(distance ≈ 369 miles)
Therefore, the distance between the two helicopters after 3 hours is approximately 369 miles. So the answer is option h) 369 miles.