For whatever reason I'm drawing a huge blank on this problem.

Shane returned from a trip to Las Vegas with $300.00, which was 50% more money than he had at the beginning of the trip. How much money did Shane have at the beginning of his trip?

x = beginning amount

300 = 1.5 x

because 50% more = 100% + 50% which is 1.5

Thank You!

$200

X+x/2=300

Put x over one and find the common denominator so that it can be added with x over 2. The common demoninator would be two. The new equation will be 2x/2+x/2=300.
Combine like terms so that the equation is 3x/2=300
then cross multiply. The equation will now be 600/3=300x/1
X=200

To solve this problem, we can use algebra to represent the relationship between Shane's initial money and the money he returned with.

Let's assume that Shane's initial money is represented by the variable "x."

We know that Shane returned with $300.00, which was 50% more than his initial money. To calculate 50% more of his initial money, we can multiply his initial money by 1.5 (1 + 50% = 1.5).

Then we can set up the equation:
x + (x * 1.5) = $300.00

Simplifying the equation:
x + 1.5x = $300.00
2.5x = $300.00

Now, we can solve for x by dividing both sides of the equation by 2.5:
x = $300.00 / 2.5
x = $120.00

Therefore, Shane had $120.00 at the beginning of his trip.