# chemistry

how much energy in calories, will be required to evaporate 125.0ml of ethanol at its boiling point?
Density=0.818g/ml
boiling point=78.5C
heat of vaporization=210 cal/g

1. 4
1. Heat= mass*Hv= volume*density*Hv

posted by bobpursley
2. 21472.5 cal

posted by Amanda

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