The number of moles of H2O produced in reaction of 50ml 1.0 M HCl and 50mL 1.0 M Naoh
.05
So many moles that you didnt know, Stupid AManDa
Ah, the magical world of moles! Let's calculate the number of moles of water produced when HCl and NaOH get together for a little reaction dance.
First, let's find the number of moles of HCl and NaOH using their given concentrations and volumes:
For HCl:
Molarity = 1.0 M
Volume = 50 mL
Volume in liters = 50 mL / 1000 mL/L = 0.05 L
Number of moles = Molarity * Volume in liters = 1.0 M * 0.05 L = 0.05 moles
For NaOH:
Molarity = 1.0 M
Volume = 50 mL
Volume in liters = 50 mL / 1000 mL/L = 0.05 L
Number of moles = Molarity * Volume in liters = 1.0 M * 0.05 L = 0.05 moles
Since the balanced chemical equation for the reaction between HCl and NaOH is:
HCl + NaOH ---> H2O + NaCl
We can see that one mole of HCl reacts with one mole of NaOH to produce one mole of water.
Therefore, the number of moles of water produced will be the same as the number of moles of HCl and NaOH, which is 0.05 moles.
So, in this reaction, 0.05 moles of H2O will be produced. And remember, when those moles gather together, it's time for a molectron dance party!
To determine the number of moles of H2O produced in the reaction between 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH, we need to use the balanced chemical equation for the reaction between HCl and NaOH.
The balanced chemical equation for the reaction is:
HCl + NaOH → H2O + NaCl
From the equation, we can see that for every one mole of H2O produced, we need one mole of HCl and one mole of NaOH.
First, let's convert the given volumes of HCl and NaOH solutions into moles.
Since the concentration of both solutions is given as 1.0 M (moles per liter), we can use the following formula:
Moles = Concentration (M) × Volume (L)
For HCl:
Moles of HCl = 1.0 M × 0.050 L (50 ml = 0.050 L) = 0.050 moles
For NaOH:
Moles of NaOH = 1.0 M × 0.050 L (50 ml = 0.050 L) = 0.050 moles
Since the balanced equation shows that the mole ratio between HCl and H2O is 1:1, the number of moles of H2O produced will also be 0.050 moles.
Therefore, the number of moles of H2O produced in the reaction between 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH is 0.050 moles.
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = 1.0 x 0.050 = ??
mols NaOH = M x L = ??
There is 1 mol H2O produced for every 1 mol HCl or 1 mol NaOH used.