physics

A potato launcher is launched at a 36 degree angle. The time the potato is in the air is 2.87 seconds and it goes 190 feet. How do I calculate the instant muzzle velocity at which it is launched?

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  1. Range = 190 feet = (V^2/g) sin (2*36)
    190 = V^2/(32.2) * sin 72

    Solve for V, in ft/s

    You did not really need to be told the value of time-in-the-air. It was calculable, using
    V cos 36 * 2.87 s = 190 ft.

    Both methods should give the same answer

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    posted by drwls

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