Write IUPAC name of the following alkanes:
1. (CH3)3-C-CH2-CH2-CH3
Would the name be 2,2-dimethylpentane?
Wouldn't it look like this:
CH3-C-CH2-CH2-CH3 with a CH3 on the top and bottom of the C, which would be the 2nd carbon... right? I don't understand why it would be the first carbon and not the second.
You mean this
CH3-C(CH3)2-CH2-CH2-CH3
that is 2,2 dimethylpentane
Notice the second carbon and attached shorthand.
I have no idea what (CH3)3-C-...looks like unless it is this
CH3-C(CH3)2-CH2-CH2-CH3 which is 2,2 dimethyl pentane. However, as I indicated above, that your (CH3)3-C- is NOT the way to write it.
To determine the IUPAC name of the given alkane, let's start by numbering the carbon chain:
(CH3)3-C-CH2-CH2-CH3
The numbering starts from the end that gives the lowest number to the substituents. In this case, we have three methyl (CH3) groups and one ethyl (CH2CH3) group. If we start numbering from the left end, the first carbon is bonded to two methyl groups (2,2-dimethyl).
Therefore, the preferred numbering is as follows:
1 - (CH3)3-C-CH2-CH2-CH3
The IUPAC name for this alkane is 2,2-dimethylpentane.
It is important to note that the first carbon that appears in the numbering is the one that gives the lowest number to the substituents in this case. In other cases, the numbering may vary depending on the substituents and their positions.