A phsician orders 750mg of chloramphenicol to be added to a 100ml bag os NS. if the drug is reconstituted to 1gm/10ml, how many mls will be added to the NS?
To find out how many milliliters (ml) of chloramphenicol will be added to the 100ml bag of Normal Saline (NS), we can use a proportion.
First, let's determine the concentration of the reconstituted solution, which is 1gm/10ml. This means that 1 gram of chloramphenicol is dissolved in 10ml of solution.
Next, we need to calculate the total amount of chloramphenicol required, which is 750mg. Since 1 gram (1gm) is equal to 1000 milligrams (1000mg), 750mg is equal to 0.75 grams (750mg / 1000mg = 0.75g).
Now, we can set up a proportion:
(1 gram / 10 ml) = (0.75 grams / x ml)
Cross multiplying, we get:
1g * x ml = 0.75g * 10ml
x ml = (0.75g * 10ml) / 1g
x ml = 7.5ml
Therefore, 7.5 milliliters of the reconstituted chloramphenicol solution will be added to the 100ml bag of NS.