A preseason game Tennessee Titans punter A.J. Trapasso hit the giant HD TV screen suspended above the field at the new Cowboys stadium. At the time of the punt A.J. was 30 yards away from the edge of the tv screen (the tv screen starts at the 40 yard line, and AJ was at the 10 yard line), and he kicked the ball straight at a 70 degree angle. How high is the video screen ?
take the tangent of 70 degrees and multiply it by 30 yards.
so it's 2100 ft ?
no, your answer makes no sense
tan 70 = h/30
h = 30tan70
h = 82.42 yds = 247.3 feet
To determine the height of the video screen, we can use trigonometry and the given information.
First, let's visualize the situation. The distance between A.J. and the video screen is 30 yards, and he kicked the ball at a 70-degree angle. We can assume that the distance between the 10-yard line and the 40-yard line (where the video screen starts) is also 30 yards.
Now, we have a right-angled triangle formed by A.J., the video screen, and the vertical distance between them. The angle at A.J. is 70 degrees, and the opposite side (the height of the video screen) is what we need to find.
Using the trigonometric function tangent (tan), we can solve for the height of the video screen. The formula for tangent is:
tan(angle) = opposite / adjacent
In this case, the angle is 70 degrees, and the adjacent side is the distance from A.J. to the edge of the screen (30 yards).
So by rearranging the equation, we can solve for the opposite side (height of the video screen):
height = tan(angle) * adjacent
height = tan(70 degrees) * 30 yards
Calculating tan(70 degrees) gives us approximately 2.74747742.
height = 2.74747742 * 30 yards
Therefore, the height of the video screen is approximately 82.422 yards.