Assuming the molor mass of paraffin is 280 g/mol, calculate the # of mols of paraffin burned. Then calculate the heat of combustion of paraffin in kJ/mol
I don't think I can help you with the information provided. We need an equation (although we can wing that one) but we also need delta H for the combustion and the number of grams of paraffin burned. If this is a problem you are solving, just type the whole thing.
To calculate the number of moles of paraffin burned, you need to know the mass of paraffin burned and its molar mass. Since the problem does not provide the mass of paraffin burned, let's assume it as, for example, 10 grams.
First, calculate the number of moles of paraffin burned:
moles = mass / molar mass
moles = 10 g / 280 g/mol
moles ≈ 0.036 moles
Now, to calculate the heat of combustion of paraffin in kJ/mol, we need the balanced equation for the combustion reaction of paraffin. Let's assume the equation is:
C25H52 + 38O2 → 25CO2 + 26H2O
Since we are assuming the number of moles of paraffin is 0.036 moles, we can see that the stoichiometric ratio of paraffin to CO2 is 25:1. Therefore, the number of moles of CO2 produced will be:
moles of CO2 produced = 0.036 moles × 25 = 0.9 moles
Now, we need to know the heat of combustion for the reaction. If it is provided, you can use that value directly. If not, you may need to look it up in a reference source such as a chemistry textbook or online database.
Let's assume the heat of combustion for paraffin is -2500 kJ/mol.
Finally, calculate the heat of combustion of paraffin in kJ/mol:
heat of combustion = (moles of CO2 produced) × (heat of combustion per mole)
heat of combustion = 0.9 moles × -2500 kJ/mol
heat of combustion = -2250 kJ/mol
Therefore, the heat of combustion of paraffin is approximately -2250 kJ/mol.