algebra

can someone please help me solve this problem?

The halftime period at a football game is 30 min long. The cheerleaders have to perform before and after the band; however, the band plays 5 min longer than the cheerleaders dance. How long does each group perform?

I am thinking the cheerleaders performed for 10 minutes and the band performed for 20 minutes. Am I correct?

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  1. Not quite.
    The cheerleaders have to perform before and after the band, that makes 10+20+10=40 minutes, and 20≠10+5.

    Let the time for each dance be D.

    "the band plays 5 min longer than the cheerleaders dance."
    Band = D+5 minutes.

    "The halftime period at a football game is 30 min long." and
    "The cheerleaders have to perform before and after the band":

    D + (D+5) + D = 30

    Solve for D.

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  2. Is it D + (D+5)+ D = 30
    5 + (15+5) + D = 30
    5 + 20 + 5 = 30

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  3. Let's try it this way:
    D + (D+5) + D = 30
    D+D+D+5 = 30
    3D+5 -5 = 30 -5
    3D = 25
    D=25/3=8 1/3 minutes

    Check:
    dance: 2 times 8 1/3 = 16 2/3 minutes
    band: 8 1/3 + 5 = 13 1/3 minutes
    Total = 16 2/3 + 13 1/3 = 30 minutes

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