it says: calculate the number of grams of NH3 produced when 21.0 g of H2 react with N2.
1. write the equation and balance it. I will help.
3H2 + N2 ==> 2NH3
2. Convert 21.0 g H2 to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles H2 to moles NH3.
4. Now convert moles NH3 to grams. # grams = moles x molar mass.
To calculate the number of grams of NH3 produced when 21.0 g of H2 reacts with N2, we need to use balanced chemical equations and stoichiometry.
1. Write the balanced equation for the reaction between H2 and N2:
N2 + 3H2 → 2NH3
2. Calculate the molar mass of H2:
The molar mass of hydrogen (H) is approximately 1 g/mol. Since H2 consists of two hydrogen atoms, its molar mass is 2 g/mol.
3. Convert the given mass of H2 to moles:
Calculate the number of moles by dividing the given mass (21.0 g) by the molar mass of H2 (2 g/mol):
Moles of H2 = 21.0 g / 2 g/mol = 10.5 mol
4. Determine the stoichiometric ratio between H2 and NH3:
The balanced equation shows that 3 moles of hydrogen react to produce 2 moles of ammonia (NH3).
5. Use stoichiometry to calculate the moles of NH3:
Since the stoichiometric ratio is 3:2 between H2 and NH3, we can find the moles of NH3 by multiplying the moles of H2 by the ratio:
Moles of NH3 = (10.5 mol H2) × (2 mol NH3 / 3 mol H2) = 7.0 mol NH3
6. Calculate the mass of NH3:
Finally, convert the moles of NH3 to grams by multiplying by the molar mass of NH3:
Mass of NH3 = 7.0 mol NH3 × (17 g/mol) = 119 g NH3
Thus, when 21.0 g of H2 reacts with N2, approximately 119 grams of NH3 are produced.