# maths

Pls help me with this...

Helen had \$140 more than Tom. Tom spent
as much as Helen at a shopping centre. How much did Tom have at first if he spent 0.8 of his money while Helen spent 2/3 of hers?

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1. H = T + 140
(H and T are what they had initially)

4T/5 = 2H/3 (equal amounts spent)

10 H = 12 T T = (5/6) H
Solve by substitution.
H = (5/6) H + 140
H/6 = 140
H = 840
T = (5/6)H = 700

Amount spent = (4/5)T = 560

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posted by drwls

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