maths

Pls help me with this...

Helen had $140 more than Tom. Tom spent
as much as Helen at a shopping centre. How much did Tom have at first if he spent 0.8 of his money while Helen spent 2/3 of hers?

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asked by danial
  1. H = T + 140
    (H and T are what they had initially)

    4T/5 = 2H/3 (equal amounts spent)

    10 H = 12 T T = (5/6) H
    Solve by substitution.
    H = (5/6) H + 140
    H/6 = 140
    H = 840
    T = (5/6)H = 700

    Amount spent = (4/5)T = 560

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    posted by drwls

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