What is the vapor pressure of (in ) at 18.5? Carbon disulfide, , has = 100 at -5.1 and = 28.0
Your question makes no sense.
in of what (water, mercury)?
18.5 what?
what does has=100 mean
-5.1 what?
=28 What?
sorry i guess the copy and paste didn't work too good
To calculate the vapor pressure of carbon disulfide (CS2) at 18.5 °C, we need to use the given Antoine equation coefficients.
The Antoine equation is commonly used to calculate vapor pressure as a function of temperature. It has the form:
log10(P) = A - (B / (T + C))
Where P is the vapor pressure, T is the temperature, and A, B, and C are constants specific to the substance.
In this case, the coefficients given are:
A = 100
B = -5.1
C = 28.0
To find the vapor pressure (P) of CS2 at 18.5 °C, we can substitute the values into the equation and solve for P:
log10(P) = 100 - (-5.1 / (18.5 + 28.0))
First, we need to determine the value inside the bracket:
(-5.1 / (18.5 + 28.0)) = -5.1 / 46.5
Next, we calculate the vapor pressure (P):
P = 10^(100 - (-5.1 / 46.5))
Using a calculator or software, we can evaluate this expression to get the vapor pressure of carbon disulfide at 18.5 °C.