Calculate the volume ( L ) of the solute C3H8O3 and the mass ( g ) of the solvent H2O that should be added to produce 6050 g of a solution that is 1.17 m C3H8O3.
You will need the density of C3H8O3. Then use molality = moles solute/kg solvent.
3.345ml
To calculate the volume of the solute C3H8O3 and the mass of the solvent H2O needed to produce a solution of 6050 g that is 1.17 m C3H8O3, we need to use the equation for molarity, which is:
Molarity (M) = moles of solute (mol) / volume of solution (L)
First, we need to calculate the number of moles of C3H8O3 in the solution. To do this, we can use the molarity and the given volume:
Molarity (M) = 1.17 m C3H8O3
Volume of solution (L) = ? (what we need to find)
We rearrange the equation to solve for the volume of the solution:
Volume of solution (L) = moles of solute (mol) / Molarity (M)
Since we are given the mass of the solution (6050 g) and the molarity (1.17 m), we can calculate the number of moles of C3H8O3:
Molar mass of C3H8O3 = 3*12.01 g/mol + 8*1.01 g/mol + 3*16.00 g/mol = 92.09 g/mol
moles of C3H8O3 = mass of C3H8O3 (g) / molar mass of C3H8O3 (g/mol)
= (1.17 mol/L) * (6050 g) / (92.09 g/mol)
Now we have the number of moles of C3H8O3 in the solution. To get the volume of solute C3H8O3 (L), we divide by the molarity:
Volume of solute C3H8O3 (L) = moles of C3H8O3 / Molarity (M)
Next, to calculate the mass of the solvent H2O, we subtract the mass of the solute C3H8O3 from the total mass of the solution:
Mass of H2O (g) = mass of the solution (g) - mass of solute C3H8O3 (g)
Now we have the volume of the solute C3H8O3 (L) and the mass of the solvent H2O (g) that should be added to produce the desired solution.