find the product of the only set of three consecutive prome numbers that differ by 2.

what is the difference between 3,5, and 7?

aren't they prime?
Can you think of any others?

What is their product ?

thanks I got it

To find the product of the only set of three consecutive prime numbers that differ by 2, we need to follow these steps:

1. Start by listing out prime numbers. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. The first few prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, and so on.

2. Look for three consecutive prime numbers that differ by 2. Let's analyze the prime numbers one by one:
- 2 and 3 differ by 1, so they do not work.
- 3 and 5 differ by 2, but they are not consecutive.
- 5 and 7 differ by 2 and are consecutive, but they are not part of a set of three consecutive primes.
- 11 and 13 differ by 2, but they are not consecutive.
- 17, 19, and 23 differ by 2 and are consecutive. This is the only set of three consecutive prime numbers that differ by 2.

3. Multiply the three prime numbers together to find the product: 17 * 19 * 23 = 7417.

Therefore, the product of the only set of three consecutive prime numbers that differ by 2 is 7417.