the digits 0,1,2,3,4,5,6,7,8,9 are repeated in such a way thatwhen the digits repeat the greatest digit is removed the pattern is repeated indefinitely what is the 1111st digit in this pattern?

To find the 1111th digit in this pattern, we need to determine which group of numbers the digit falls into (i.e., the thousands group, the hundreds group, etc.) and then identify the specific digit within that group.

Since the pattern repeats indefinitely, we can first determine the length of one complete repetition. In this case, the length of one repetition is the sum of the digits from 0 to 9, which is 45.

To determine which group of numbers the 1111th digit falls into, we need to divide the position number (1111) by the length of one repetition (45) and take the ceiling value to get the full number of repetitions. In this case, 1111 ÷ 45 = 24.68. Taking the ceiling value of 24.68, we get 25 repetitions.

Next, we subtract the product of the full number of repetitions (25) and the length of one repetition (45) from the position number to determine where our digit falls within the final repetition. In this case, 1111 - (25 × 45) = 1111 - 1125 = -14.

Since the result (-14) is negative, we know that we are looking for the 14th digit from the end of the final repetition. To find this position, we can add the result (-14) to the length of one repetition (45) and take the absolute value to eliminate the negative sign. In this case, |(-14 + 45)| = |31| = 31.

So, the digit in the 1111th position is the 31st digit from the end of the final repetition.

Now, we need to determine which digit corresponds to the 31st position from the end. We can do this by subtracting the position from the length of one repetition and then taking the remainder after dividing by 10. In this case, (45 - 31) % 10 = 14 % 10 = 4.

Therefore, the 1111th digit in this pattern is 4.