Calculate Ke for the following (equilibrium concentrations given below substances)
H2(g)+Br2(g) yields 2HBr(g) + heat[.513] [.62] [.346]
Thank you!
The concentrations didn't show up correctly...they should be
H2=[.513]
Br2=[..62]
2HBr=[.346]
thank you!
Same things as above.
To calculate the equilibrium constant (Ke) for the given reaction, we need to use the formula for Ke:
Ke = ([HBr]^2) / ([H2][Br2])
In the reaction, we can see that the concentrations of HBr, H2, and Br2 are given. These concentrations correspond to the equilibrium concentrations, denoted by [HBr], [H2], and [Br2], respectively.
Using the given concentrations, we can substitute the values into the formula for Ke:
Ke = ([HBr]^2) / ([H2][Br2])
Ke = (0.346^2) / (0.513 * 0.62)
Ke = 0.119 / 0.31876
Ke ≈ 0.373
Therefore, the equilibrium constant (Ke) for the given reaction is approximately 0.373.