Chemistry

Just checking to see if my answers are correct.
5mL of 0.1M NaOH and 5mL water.
Pouring 1mL of solution from 1st test tube, 2nd to 3rd, etc.
Concentration NaOH .1M
Concentration pOH pH
#1) .05 -log(.05)=1.3 14-1.3=12.7
#2) .005 -log(.005)=2.3 14-2.3=11.7

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asked by linda
  1. hi iwant to answer question

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    posted by shara
  2. ok. There should be spaces between 0.05M pOH= -log(.05)=1.3 pH= 14-2.3=11.7

    TT #2
    Concentration =0.005M
    pOH= -log(0.005)=2.3
    pH= 14-2.3=11.7

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    posted by linda

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