If a student is selected at random, what is the probability he or she prefers meat toppings ?
68 students prefer cheese
79 students prefer meat
70 students prefer veggie
70/208, 35/104 or 1/3 is that correct ?
79 prefer meat. Divide that by the total number of students to get the probability.
To find the probability of a student randomly selected preferring meat toppings, we need to divide the number of students who prefer meat toppings by the total number of students.
You correctly identified that there are 79 students who prefer meat toppings. However, the total number of students is the sum of the number of students who prefer different toppings: 68 (cheese) + 79 (meat) + 70 (veggie) = 217.
Therefore, the probability of a student randomly selected preferring meat toppings is 79/217.
Simplifying this fraction, we get 1/2.75. Multiplying the numerator and denominator by 4, we get 4/11. So the probability is 4/11, which is approximately equal to 0.3636.