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Give the equation of the line that passes through point (5, 1) and is parallel to the line y = 3x – 1.
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Give the equation of the line that passes through point (5, 1) and is parallel to the line y = 3x – 1.
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you know the slope of the line parallel: 3 y=3x+b PUt in the point (5,1) and solve for b.
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Give the equation of the line that passes through point (-5, -1) and is parallel to the line y = -
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. Give the equation of the line that passes through point (5, 1) and is parallel to the line y = 3x – 1. Please help, I am so
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The line passing through (x1,y1) and parallel to y=mx+b is (y-y1)=m(x-x1) Substitute (5,1) for
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<-1+3t,6+t> or y-6 = 1/3 (x+1)
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Give the equation of the line that passes through point (5, 1) and is parallel to the line y = 3x – 1.
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slope of the line will be same to that of the given line i.e. 3 Now let the eq. be y -3x = m (where
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Give the equation of the line that passes through point ( 1, -3) and is parallel to the line y = 2x - 8.
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Since your new line is parallel to y = 2x + 8, it must differ only in the constant, so let it by y =
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Give the equation of the line that passes through point (-5, -1) and is parallel to the line y = -1/4x- 7.
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Since the new line must be parallel to the old line, it must have a slope of -1/4 so let its
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Give the equation of the line that passes through point (1, 2) and is parallel to the line y + 6x -7 = 0.
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y - y1 = m(x - x1) Any line parallel to the line y + 6x - 7 = 0 must have the same slope --- m. The
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Give the equation of the line that passes through (-5,-1) and is parallel to the line y=-1/4x
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