How many ways can 3 students be arranged in three chairs? I'm not really sure but I think that the answer will be 9 (nine), is that correct..?
No, it is 6 ways.
Think it through this way:
The first chair can be filled in 3 ways, for each of those the second chair in 2 ways, leaving only one way to fill the 3rd chair.
So ...
3x2x1 = 6
To find the number of ways 3 students can be arranged in three chairs, we can use the concept of permutations.
Permutations represent the number of ways objects can be arranged in a specific order. In this case, we want to find the number of permutations when arranging 3 students in 3 chairs.
The formula for permutations is nPr = n! / (n - r)!, where n is the total number of objects, and r is the number of objects being arranged at a time.
Using this formula, we have n = 3 (the number of students) and r = 3 (the number of chairs), so we can calculate it as follows:
3P3 = 3! / (3 - 3)!
= 3! / 0!
= 3! / 1
= 3 x 2 x 1 / 1
= 6
Therefore, there are 6 ways to arrange the 3 students in 3 chairs, not 9. Each student can be placed in a chair in 3 different ways, but since the order matters, the number of arrangements reduces to 6.