while driving his sports car at 20.0 m/s down a four-lane highway, eddie comes up behind a slow-moving dump truck and decides to pass it in the left lane. If eddie can accelerate at 5.00 m/s2) (squared) how long will it take for him to reach a speed of 30.0 m/s?
i know its
Vfinal=Vinitial+acceleration*time but i don't know what 5.00 m/s2 (squared) means...
would it be 30.0 = 20.0 + 5.00 m/s^2 (squared) * time, but i have to solve for time..... whats the squared for....? can you write me this equation in numbers so i can just slove it, because i know how it goes just the squared confuses me....
5.00 m/s^2 is the acceleration rate of the passing car. Multiply it by the time interval for the velocity change/ You havew already written the correct equation. Solve if for t.
t = (10 m/s)/(5 m/s^2)
Your answer will be in seconds
To clarify, the squared symbol (²) in this context means that the unit is being squared, not the actual value. In this case, the unit is meters per second (m/s). So, 5.00 m/s² means 5.00 meters per second per second, or 5.00 m/s².
Now, let's write the equation using numbers. You want to find the time it takes for Eddie to reach a speed of 30.0 m/s, starting from an initial speed of 20.0 m/s, with an acceleration of 5.00 m/s².
The equation you need to use is:
Vf = Vi + at
Where:
Vf = final velocity (30.0 m/s in this case)
Vi = initial velocity (20.0 m/s)
a = acceleration (5.00 m/s²)
t = time (what we want to find)
Plugging in the known values into the equation, we can solve for time:
30.0 = 20.0 + 5.00 * t
Now, let's isolate 't' by rearranging the equation:
30.0 - 20.0 = 5.00 * t
10.0 = 5.00 * t
To solve for 't', divide both sides of the equation by 5.00:
t = 10.0 / 5.00
t = 2.0 seconds
So, it will take Eddie 2.0 seconds to reach a speed of 30.0 m/s.