Four different positive integers sum to one hundred twenty-five. If you increase one of these numbers by four, decrease the second by four, the multuply the third by four, and divide the last by four, you will produce four equivalent numbers. What are the four original numbers that sum to 125?

If you interpret the question, you can come up with a system of equations to solve, for example:

w + x + y + z = 125
w + 4 = x - 4
3y = z/4
x - 4 = 3y

The first equation comes from the first statement that the four numbers sum to 125. The other three come from the second statement about changing the numbers to make them all equivalent. You can solve the system from here.

To find the four original numbers that sum to 125, we can set up a system of equations.

Let's assume the four numbers are a, b, c, and d.

From the given information, we can write the following equations:

a + b + c + d = 125 (Equation 1) - This equation represents the sum of the four original numbers.

(a + 4) = (b - 4) = (c × 4) = (d ÷ 4) (Equation 2) - This equation represents the conditions for producing four equivalent numbers by performing the given operations.

To solve this system of equations, we'll use substitution.

From Equation 2, we have:
a + 4 = b - 4
a = b - 8 (Equation 3)

Also, from Equation 2, we have:
a + 4 = c × 4
c = (a + 4) ÷ 4
c = (b - 8 + 4) ÷ 4
c = (b - 4) ÷ 4
c = (b ÷ 4) - 1 (Equation 4)

Furthermore, from Equation 2, we have:
a + 4 = d ÷ 4
d = (a + 4) × 4
d = (b - 8 + 4) × 4
d = (b - 4) × 4
d = 4b - 16 (Equation 5)

Substituting Equations 3, 4, and 5 into Equation 1, we get:

(b - 8) + b + ((b ÷ 4) - 1) + (4b - 16) = 125

Combining like terms:
2b + (b ÷ 4) + (b - 9) = 125

Multiplying through by 4 to eliminate the fraction:
8b + b + 4(b - 9) = 500

Simplifying further:
8b + b + 4b - 36 = 500
13b - 36 = 500
13b = 536
b = 41.23

Since the numbers are required to be positive integers, we need to find another approach, as b is not an integer.

It seems there might be an error or inconsistency in the information provided. Could you please double-check the question or provide additional information if available?