if a single letter is drawn from the set (m, a, t, h, e, i c, s) what is the probability that the letter drawn is a member of the set (m,a, t,h)
4/8 or 1/2
I was thinking since there are 8 numbers in the first set, and your drawing out 4. the probability would be 50%, 4/8 or 1/2
Does that sound correct?
Yes.
To find the probability of drawing a letter from the set (m, a, t, h) from the larger set (m, a, t, h, e, i, c, s), we need to determine the size of each set and calculate the ratio between them.
There are 8 letters in total in the larger set (m, a, t, h, e, i, c, s). Out of these 8 letters, 4 of them (m, a, t, h) are in the smaller set.
The probability of drawing a letter from the smaller set is given by:
P(letter from smaller set) = (number of favorable outcomes) / (total number of possible outcomes)
In this case, the number of favorable outcomes is 4, representing the four letters (m, a, t, h) in the smaller set.
The total number of possible outcomes is 8, representing the total number of letters in the larger set.
So, the probability of drawing a letter from the set (m, a, t, h) is:
P(letter from smaller set) = 4 / 8
Simplifying this fraction, we get:
P(letter from smaller set) = 1 / 2
Therefore, the probability of drawing a letter from the set (m, a, t, h) is 1/2 or 0.5, which is equivalent to 50%.