Infrared, ultraviolet, and visible radiation are all part of the electromagnetic spectrum.
Arrange the three types of radiation in order of increasing energy?
i put visible<infrared<ultraviolet. Is this correct though
Close but no cigar. You can make an educated guess by remembering that
E = hf. You know uv is high frequency(short wavelength) so it will have the most energy. Infrared is low frequency (high wavelength) so it will have the least energy. Visible radiation is between. BTW, the problem you had the other night where I suggested it might be the number of significant digits. It was a percent problem. How did that work out?
u were right on that significant figure. Thanks for the help
Yes, your arrangement is correct. The order of increasing energy for these three types of radiation is:
Visible < Infrared < Ultraviolet
To understand why, we need to look at the electromagnetic spectrum. The electromagnetic spectrum is a range of all the different types of electromagnetic radiation, arranged in order of increasing frequency or decreasing wavelength.
Invisible radiation, such as infrared, has longer wavelengths and lower frequencies compared to visible light. It carries less energy than visible light.
Visible light is the part of the electromagnetic spectrum that is visible to the human eye. It has a range of wavelengths and corresponding colors, with red having the longest wavelength and violet having the shortest. Visible light has more energy than infrared radiation and less energy than ultraviolet radiation.
Ultraviolet radiation has shorter wavelengths and higher frequencies compared to visible light. It carries more energy than both infrared and visible light.
Therefore, the correct order of increasing energy for these three types of radiation is:
Visible < Infrared < Ultraviolet