Physics

What should be the angle between two vectors of magnitudes 3.20 and 5.70 units, so that their resultant has a magnitude of 6.10 units?

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  1. Use the law of cosines.
    c^2 = a^2 + b^2 - 2ab cos C
    6.1^2 = 3.2^2 + 5.7^2 - 2*3.2*5.7 cos C
    cos C = (10.24 + 32.49 - 37.21)/36.84
    = 0.1498
    Solve for C and verify my numbers.

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