sulfamic acid, HSO3NH2, is a strong monoprotic acid that can be used to standardize a strong base :
HSO3NH2(aq)+ KOH(aq) --> KSO3NH2(aq) + H20(l)
A .179g sample of HSO3NH2 required 19.4 mL of an aq soln of KOH for complete reaction. whats the molarity of KOH soln?
see below.
To find the molarity of the KOH solution, we can use the given information about the mass of the HSO3NH2 sample and the volume of KOH solution required for complete reaction.
1. Determine the number of moles of HSO3NH2:
- Calculate the molar mass of HSO3NH2:
H: 1.00794 g/mol x 1 = 1.00794 g/mol
S: 32.06 g/mol x 1 = 32.06 g/mol
O: 15.9994 g/mol x 3 = 47.9982 g/mol
N: 14.0067 g/mol x 2 = 28.0134 g/mol
Add up the molar masses: 1.00794 + 32.06 + 47.9982 + 28.0134 = 109.07954 g/mol
- Calculate the number of moles of HSO3NH2:
moles = mass / molar mass
moles = 0.179 g / 109.07954 g/mol
2. Determine the number of moles of KOH:
- From the balanced equation, we know that the ratio between HSO3NH2 and KOH is 1:1.
- Therefore, the number of moles of KOH is equal to the number of moles of HSO3NH2.
3. Determine the volume of the KOH solution in liters:
- Convert the volume of the KOH solution to liters:
19.4 mL = 19.4 mL / 1000 mL/L
4. Calculate the molarity of the KOH solution:
- Molarity (M) is defined as moles of solute divided by liters of solution.
- Molarity (M) = moles of KOH / volume of KOH solution
- Molarity (M) = moles of HSO3NH2 / volume of KOH solution
- Molarity (M) = (0.179 g / 109.07954 g/mol) / (19.4 mL / 1000 mL/L)
Now you can perform the calculation to find the molarity of the KOH solution.
To find the molarity of the KOH solution, we can use the equation:
Molarity (M) = moles/volume (L)
First, we need to determine the moles of HSO3NH2 used in the reaction. We can do this by using the given mass of the sample and its molar mass:
Molar mass of HSO3NH2 (HSO3NH2) = 97.09 g/mol
moles of HSO3NH2 = mass/molar mass
= 0.179 g / 97.09 g/mol
= 0.001845 mol
Now we can determine the molarity of KOH solution by dividing the number of moles of KOH used by the volume of the solution in liters:
Molarity of KOH = moles/volume
= 0.001845 mol / 0.0194 L
= 0.095 M
Therefore, the molarity of the KOH solution is 0.095 M.