You REALLY should read questions you post. The typos make this almost useless; however, I will assume you meant to write, ".....and 21.0 g Mg(OH)2 is recovered?"
Mg + 2HOH ==> Mg(OH)2 + H2
1. Convert 10.1 g Mg to moles. Moles = grams/atomic mass.
2. Using the coefficients in the balanced equation, convert moles Mg to moles Mg(OH)2.
3. Now convert moles Mg(OH)2 to grams. grams = moles x molar mass.The value, in grams, which you obtain here is the THEORETICAL YIELD.
4. Now that you have the theoretical yield, you can calculate the percent yield.
%yield = (grams obtained/theoretical yield)*100 =??
For the second part, start with 24 g Mg and determine the theoretical yield. Then multiply by 0.95 to obtain the actual yield if the process is 95% efficient.
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