3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1/3) tanu=sq. root of (3)/3 tanu=sq. root of 1 Did I do this one right? If not, could you please show me the correct method?? Thanks!
From tanu=sq. root of (3)/3 The next step would be u = tan^-1[1/(sqrt3)]= 30 degrees (or 210 degrees) Your first steps are OK, until the last line.
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