A bin contains 8 blue chips, 5 red chips, 6 green chips, and 2 yellow chips.
Question: drawing a red chip, replacing it, then drawing a green chip.
A bin contains 8 blue chips, 5 red chips, 6 green chips, and 2 yellow chips
Drawing a red chip, replacing it, then drawing a green chip.
Selecting two yellow chips without replacement
Choosing green, then blue, then red without replacing each chip
The number of chips of any particular color divided by the total number of chips is the probability. If there is replacement, the total number of chips remains the same.
To find the probability of 2 or more events all occurring, multiply the probability of the individual events.
I hope this helps.
5 6
- x - = 30 10
21 21 -- -> --
441 147
there you go(:
look at that like a fractiion byy the waay!!
To find the probability of drawing a red chip, replacing it, and then drawing a green chip, we need to consider the total number of chips in the bin and the number of red and green chips specifically.
1. Determine the total number of chips:
The bin contains 8 blue chips + 5 red chips + 6 green chips + 2 yellow chips, which gives us a total of 21 chips.
2. Determine the probability of drawing a red chip:
Out of the 21 chips, there are 5 red chips. Therefore, the probability of drawing a red chip is 5/21.
3. Replace the red chip back into the bin:
Since we are replacing the red chip back into the bin, the number of red chips remains unchanged at 5.
4. Determine the probability of drawing a green chip:
Out of the 21 chips, there are 6 green chips. Therefore, the probability of drawing a green chip is 6/21.
5. Calculate the probability of the sequential events:
To find the probability of two independent events occurring sequentially, we multiply the probabilities of each event. So, the probability of drawing a red chip, replacing it, and then drawing a green chip is (5/21) * (6/21).