# bearing

Three towns p, q and r are such that the distance between p and q is 50km and the distance between p and r is 90km. If the bearing of q from p is 075 and the bearing of r from p is 310, find the
(a)distance between q and r
(b)bearing of r from q

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1. Ok, the angle at p is between 310 and 075,or an angle of 125 (check that). YOu have two sides, one angle

find another angle with the law of sines.
then find the last angle (sum of angles is 180)
then find the last side by law of sines.

Make certain you draw the figure, life is simpler with a drawing.

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bobpursley
2. thank you, although am still hooked

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3. 254

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4. All angles are measured CW from +y-axis
a. PQ + QR = PR.
QR = PR - PQ = 90[310o] - 50[75o],
QR = (90*sin310-50*sin75) + (90*cos310-50*cos75)i,
QR = -117.2 + 44.9i = 125.5km[-69o] = 125.5km[291o] CW.

b. Bearing = 291o CW.

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