a 17 of model plane is flying at a horizontal speed of 14 m/s
the plane goes into a dive and levels off 21 m closer to the earth what was the ammount of potentiomal energy lost in the dive
a 17 kg
P.E. loss = M g H
= 17 kg * 9.8 m/s^2 * 21 m = 3500 J
The speed does not matter
To determine the amount of potential energy lost in the dive, we need to find the change in height of the model plane.
First, let's determine the initial potential energy of the model plane (before the dive). The potential energy (PE) of an object is given by the formula:
PE = m * g * h
Where:
m is the mass of the object (in kilograms)
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
h is the height above a reference point (in this case, the ground)
Since the model plane is flying horizontally, there is no change in its horizontal height. Therefore, we only need to consider the vertical change in height.
Let's assume the initial height of the plane before the dive is denoted as h1, and the final height after leveling off is denoted as h2. The change in height, Δh, can be calculated as:
Δh = h1 - h2
Now, we have two situations: the initial scenario (before the dive) and the final scenario (after leveling off).
In the initial scenario, the potential energy (PE1) is given by:
PE1 = m * g * h1
In the final scenario, the potential energy (PE2) is given by:
PE2 = m * g * h2
The change in potential energy (ΔPE) is the difference between the initial and final potential energy:
ΔPE = PE1 - PE2
Substituting the formulas for PE1 and PE2, we get:
ΔPE = (m * g * h1) - (m * g * h2)
Since we only need to determine the amount of potential energy lost, we are interested in the magnitude of ΔPE. Therefore, we can neglect the negative sign.
To solve for ΔPE, we need to know the values of the mass of the model plane (m), the initial height (h1), and the final height (h2).
Please provide these values and we can calculate the amount of potential energy lost in the dive.