calculate the heat energy required to raise the temperature of a 500 gram iron pipe from 25 degrees celcius to 100 degrees celcius
Q = m*Cp*(delta t)
The delta t is given as 100-50 = 50 degrees Celsius.
The mass is given as 500g, or 0.5kg.
The specific heat, Cp, of Iron, is 449J/kg/K.
Q = ?
Note the correct spelling of celsius.
Oops I meant delta t = 100 - 25 = 75 degrees Celsius.
To calculate the heat energy required to raise the temperature of an object, you need to use the formula:
Q = mc∆T
Where:
Q = heat energy (in joules)
m = mass of the object (in grams)
c = specific heat capacity of the material (in joules/gram °C)
∆T = change in temperature (in °C)
In this case, the mass of the iron pipe is 500 grams (m), and the change in temperature is from 25°C to 100°C (∆T = 100°C - 25°C = 75°C).
To find the specific heat capacity (c) of iron, you need to look it up in a reference source or use an average value. The specific heat capacity of iron is about 0.45 joules/gram °C.
Now, substituting the values into the formula:
Q = 500g * 0.45 J/g°C * 75°C
Calculating:
Q = 16,875 joules
Therefore, the heat energy required to raise the temperature of a 500-gram iron pipe from 25°C to 100°C is 16,875 joules.