physics

A diffraction grating gives a second-order maximum at as angle of 31�‹ for violet light (ƒÉ = 4.0 �~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

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asked by Rach
  1. Sorry about the double post, and
    the question is:
    A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

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    posted by Rach
  2. n lambda = d sin( theta )

    d=n * lambda/sinTheta

    solve for d. That is the distance between slits, so lines/distance= 1/d

    change wavelength to cm if you want lines per cm

  3. isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?

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    posted by Rach
  4. so n= 2 (second order)
    theta= 31 degrees
    d= 0.1 m
    lambda= 4.0 x 10^-7 m

    (i'm required to solve in m)

    is this correct?

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    posted by Rach
  5. no

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