I am supposed to find five ordered pairs to make the equation true
y = 20 + x/3
so far I have (0,20) and (6,22) is this right?
I am unsure because my text example had
x^2 + 3x = y
(0,0) (1,4) (2,10) (3,18) (4,28)
and they have a common theme (muliply by by 0 then 4, 5, 6, and 7) should mine be like this?
To find the ordered pairs that satisfy the equation y = 20 + x/3, you can substitute different values for x and solve for y.
Let's find the first ordered pair:
Substitute x = 0 into the equation:
y = 20 + 0/3
y = 20 + 0
y = 20
So the first ordered pair is (0, 20).
Let's find the second ordered pair:
Substitute x = 6 into the equation:
y = 20 + 6/3
y = 20 + 2
y = 22
So the second ordered pair is (6, 22).
Now, let's check if there is a common pattern by using other values for x:
Substitute x = 12 into the equation:
y = 20 + 12/3
y = 20 + 4
y = 24
So the third ordered pair is (12, 24).
Substitute x = 18 into the equation:
y = 20 + 18/3
y = 20 + 6
y = 26
So the fourth ordered pair is (18, 26).
Substitute x = 24 into the equation:
y = 20 + 24/3
y = 20 + 8
y = 28
So the fifth ordered pair is (24, 28).
Therefore, the correct ordered pairs that satisfy the equation y = 20 + x/3 are:
(0, 20), (6, 22), (12, 24), (18, 26), and (24, 28).
It seems that in your other example with the equation x^2 + 3x = y, there is a common pattern where you multiply x by consecutive numbers. However, that pattern may not always be present in every equation. In this case, the pattern does not apply. You should find the ordered pairs by substituting different values for x and solving for y.